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jeyben [28]
4 years ago
7

PLZ HELP WILL GIVE BRAINLIEST!!!!!!!!!! AND 20 POINTS!!!!!!!!!!!

Mathematics
1 answer:
Free_Kalibri [48]4 years ago
6 0

Answer:

the number less than 84 are "80, 81, 82, 83" four numbers and all numbers together 7 num "80, 81, 82, 83, 84, 85, 86"

4/7 x 100 = 57.142858%

57.1%

~batmans wife dun dun dun....

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06.05 LC)
lesantik [10]
The correct answer is didn’t ya because the other ones are not correct
6 0
4 years ago
HELP PLEASE!!!!!!
wel

Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

<h3>The average annual rate of change</h3>

The given parameters are:

Value in 1990 = $12,500

Value in 2009 = $20,050

The average annual rate of change is then calculated as:

Rate of change = Difference in the values/Difference in the years

So, we have:

Rate of change = (20050 - 12500)/(2009 - 1990)

Evaluate

Rate of change = 397.37

<h3>Pat and cable car</h3>

<u>The complete table of average rate of change</u>

The average rate of change is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

<em>0 - 2 minutes</em>

Pat = (125 - 0)/(2 - 0) = 62.5

Cable = (100 - 0)/(2 - 0) = 50

<em>2 - 4 minutes</em>

Pat = (200 - 125)/(4 - 2) = 37.5

Cable = (200 - 100)/(4 - 2) = 50

<em>4 - 5 minutes</em>

Pat = (225 - 200)/(5 - 4) = 25

Cable = (250 - 200)/(5 - 4) = 50

So, the complete table is:

Time   0 - 2 minutes     2 - 4 minutes    4 - 5 minutes

Pat           62.5                     37.5                   25

Cable       50                         50                      50

<h3>Is the rate of change constant for Pat? Is it constant for the cable car? </h3>

The rate of change is not constant for Pat, while the rate of change is constant for the cable car

This is so because, we have different values for the rate of change for Pat, while we have only one value for the rate of change for Cable car

<h3>The average rate of change over the entire trip up the mountain</h3>

This is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

Pat = (250 - 0)/(6 - 0) = 41.7

Cable = (250 - 0)/(5 - 0) = 50

Hence, Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

Read more about average rate of change at

brainly.com/question/2170564

#SPJ1

6 0
2 years ago
Help me please struggling
Sedbober [7]

Answer:

i think it is 27 because the last one adds up to 27

i am not really good at this stuff

3 0
3 years ago
Luna invested $8000 for 36 months at an interest rate of 4.8% per month. How much money will Luna have at the end of her investm
Degger [83]

Answer : $ 9, 152

Luna invested $8000 for 36 months at an interest rate of 4.8%

Let P = principal

T = time

r = rate

Using the simple interest,

\begin{gathered} I\text{ =}\frac{P\text{ x R x T}}{100} \\ P\text{ = \$8000} \\ r\text{ = 4.8\%} \\ t\text{ = 36 months} \\ 12\text{ months = 1 year} \\ 36\text{ months = x year} \\ \text{Cross multiply} \\ 12\cdot\text{ x = 1 x 36} \\ 12x\text{ = 36} \\ \text{Divide both sides by 12} \\ x\text{ = 36/12} \\ x\text{ = 3 years} \\ \text{Hence, t = 36 months = 3 years} \\ I\text{ = }\frac{8000\text{ x 3 x 4.8}}{100} \\ I\text{ = }\frac{115,\text{ 200}}{100} \\ I\text{ = \$1, 152} \end{gathered}

The total balance = Interest + principal

Balance = 1, 152 + 8000

Balance =$9, 152

The total money she will have at the end of the investment is $9, 152

3 0
1 year ago
A simple random sample of 100 men is chosen form a population with mean height 71 in and standard deviation 2.5 in. What is the
ankoles [38]

Answer:

2.28%

Step-by-step explanation:

The z score is used to determine how many standard deviations that the raw score is above or below the mean. If the z score is positive then the raw score is above the mean and if it is negative then it is below the mean. It is given by:

z=\frac{x-\mu}{\sigma}\\ \\\mu = mean, \sigma=standard\ deviation,x=raw\ score\\\\For\ a\ sample\ n\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\For\ x

5 0
4 years ago
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