A student leaving school walks 2.8 km north and then walks 1.2 km south. What is
2 answers:
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Answer:
Step-by-step explanation:
Given equation is,
y=-0.5x-2
when x=-2 , y=-0.5(-2)-2=1-2=-1
when x=0 , y=-0.5(0)-2=0-2=-2
when x=2 , y=-0.5(2)-2=-1-2=-3
So, we get the points (-2,-1) , (0,-2) , (2,-3)
Now, using the points on the graph and adding them, we will get the graph of given line.
Please check image for the graph.
Now for the second part- we have to find values of x , for which y is positive.
That means, y will be above the x-axis.
From the graph we can see that- when x<-4,
then the graph is above the x-axis.
So, for all values of x, which are less than -4,
we will get the positive graph.
