Answer:
Graph G
Step-by-step explanation:
The graphs are attached
Given that the oil-well contractor drills a shaft 7 meters deeper into the ground every 2 hours, hence the rate at which the shaft drills = 7 meter / 2 hours = 3.5 meters per hour
Since the drill goes into the ground, hence the rate is negative that is -3.5 meters per secong
The slope (rate of change) of a line (m) is given by:

a) For graph F, the line passes through the point (0,0) and (10, -20). Hence:

b) For graph G, the line passes through the point (0,0) and (10, -70). Hence:

c) For graph H, the line passes through the point (0,0) and (10, -35). Hence:

d) For graph J, the line passes through the point (0,-3.5) and (10, -3.5). Hence:
