Answer: height of building = 18.8m
Explanation: The question is a projectile motion, a two dimensional motion with a vertical constant acceleration (g = - 9.8m/s²) and a constant horizontal velocity (thus making horizontal component of acceleration zero).
From the question, distance between bottom of building and where the object lands = 64m, initial velocity for throwing the object = 19.6m/s
The horizontal range formulae is given as
d= vt
Where d= horizontal range = 64m, v = initial velocity of throw.
64 = 19.6 × t
t = 64/ 19.6
t = 3.265 s.
Height (h) of the building is gotten by using the formulae
h =vt - 1/2gt²
h = (19.6×3.265) - 1/2×9.8×(3.265)²
h = 71.05 - (104.47/2)
h = 71.05 - 52.235
h = 18.8m
Answer:
(a). I' = 17.24 A
(b).The current in second wire is in opposite direction compare to first wire.
Explanation:
Given data
r = 0.038 m
4.9 × 
I = 0.54 A
(a). The current in the second wire is calculated as
Put all the values in above formula we get
I' = 17.24 A
(b). The current in the two wires is in opposite directions because the wires repeal each other. therefore the current in second wire is in opposite direction compare to first wire.
Answer:
2.28 s
Explanation:
Let g = 9.8 m/s2 and neglect air resistance. The box of sand with an initial velocity of 4.2m/s in free fall would yield the following equation of motion
t = 2.28 or t = -3.14
Since t can only be positive we will pick t = 2.28
s
Answer:
The generator will work only if the magnetic field associated with the turns of coil change.
here both magnet and coil are stationary with respect to each other so no electromagnetic induction would take place. so no indiced current will be produced.
the student has to introduce some mechanism either to rotate the coil or the magnet
That is potential energy.
