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Triss [41]
3 years ago
13

A form of erosion in which particles of sand or dust rub across the surface of rocks.

Physics
2 answers:
gayaneshka [121]3 years ago
7 0
The answer is B) Abrasion.
Likurg_2 [28]3 years ago
5 0
Your answer will be Abrasion 

Hope i helped have a wonderful day.
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The electrons in the beam of a television tube have an energy of 19.0 keV. The tube is oriented so that the electrons move horiz
igomit [66]

Answer:

The direction is due south

Explanation:

From the question we are told that

     The energy of the electron is E = 19.0keV = 19.0 *10^3 eV

      The earths magnetic field is B = 42.3 \muT = 42.3 *10^{-6} T

     

Generally the force on the electron is perpendicular to the velocity of the elecrton and the magnetic field and this is mathematically reresented as

          \= F = q (\= v * \=B)

On the first uploaded image is an  illustration of the movement of the electron

    Looking at the diagram  we can see that in terms of direction  the magnetic force  is

             \= F  =q(\=v * \= B)= -( -\r i * - \r k)

                = -(- (\r i * \r k))

generally  i cross k = -j

      so the equation above becomes

             \= F = -(-(- \r j))

                = - \r j

This show that the direction is towards the south  

 

3 0
3 years ago
a ball of 5 kg is moving towards the wall at 6 m/s. after a while, it hits the wall and rebounds back at 4 m/s in the opposite d
iris [78.8K]

Answer:-50 J

Explanation:

3 0
3 years ago
Which describes the molecular motion of a solid nickel marble rolled across the floor?
Gemiola [76]
I can't decide between A and B, but B seems more likely to me. Even though the molecules don't look like they're moving, the area of contact is slightly more compressed.
7 0
3 years ago
In the year 2055, a rocket was launched from a research laboratory on Mars. Mars has essentially no atmosphere. The test rocket
algol [13]

Answer:

h = 618.64 m

Explanation:

First we need to calculate the height gained by rocket while the fuel is burning. We use 2nd equation of motion for that purpose:

h₁ = Vit + (1/2)at²

where,

h₁ = height gained during the burning of fuel

Vi = Initial Velocity = 0 m/s

t = time = 7 s

a = acceleration = 8 m/s²

Therefore,

h₁ = (0 m/s)(7 s) + (1/2)(8 m/s²)(7 s)²

h₁ = 196 m

Now we use 1st equation of motion to find final speed Vf:

Vf = Vi + at

Vf = 0 m/s + (8 m/s²)(7 s)

Vf =  56 m/s

Now, we calculate height covered in free fall motion. Using 3rd equation of motion:

2ah₂ = Vf² - Vi²

where,

a = - 3.71 m/s²

h₂ = height gained during free fall motion = ?

Vf = Final Velocity = 0 m/s (since, rocket will stop at highest point)

Vi = 56 m/s

Therefore,

(2)(-3.71 m/s²)h₂ = (0 m/s)² - (56 m/s)²

h₂ = 422.64 m

So the total height gained will be:

h = h₁ + h₂

h = 196 m + 422.64 m

<u>h = 618.64 m</u>

4 0
2 years ago
An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only
alexira [117]

Answer:

The answer is "2.352 \ \frac{m}{s}"

Explanation:

\to mass(m_1)=102 \ kg\\\\\to  mass(m_2)=10 \ kg \\\\\to v=2.10\ \frac{m}{s}\\\\

momentum before:

\to p=(m_1+m_2)v

       =(102+10)2.10\\\\=(102\times 2.10 +10 \times 2.10)\\\\=214.2+21\\\\=235.2

momentum After:

\to p=(m_1+m_2)v

       =(102\times 0 +10 \times v)\\\\ =(0 +10v)\\\\=10v\\

Calculating the conservation of momentum:

\to \text{momentum before = momentum After}

\to 235.2=10v\\\\\to v= \frac{235.2}{10}\\\\ \to v=2.352 \ \frac{m}{s}

3 0
2 years ago
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