I just took this test, the answer is 196 m^2, I got it right
I’m going to assume initial velocity is 0.
Use Newton’s second law:
F = m•a
F/m = a
14.0/32.5kg= 28/65 m/s^2
Use constant SUVAT acceleration formulae:
S- displacement - what we need to find out
U - initial velocity - 0
V
A - 28/65 m/s^2
T - 10 seconds
S = ut + 1/2at^2
Since u = 0
S = 1/2at^2
1/2• 28/65 • 10^2 = 21.5metres~
Answer is 21.5 metres
~Hoodini, here to help.
Answer:
They are very distant.
Explanation:
With relativistic red shifts that take into account dilation of space-time, as Einstein predicted.
Elastic potential energy stored in a spring is
(1/2) · (spring constant) · (stretch or compress)² .
PE = (1/2) · (100 N/m) · (0.1 m)²
PE = (50 N/m) · (0.01 m²)
PE = (50 · 0.01) (N · m / m²)
PE = 0.5 N · m
PE = 0.5 Joule
speed of the striking object is given as
now this speed in SI units given as
So here we can use kinematic now to find the height from where it is dropped
so here we will have
now we have
now from above equation
now we know that average height of 1 story building is 3 meter
so approx total number of stories in the building will be
