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astra-53 [7]
4 years ago
8

Tell me the answers please!

Mathematics
1 answer:
il63 [147K]4 years ago
4 0
18 is D and 19 is C you're welcome
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What is 1 fourteenth as a decimal
nataly862011 [7]
1 14'th as a decimal would be 1/14 or 0.0714 (rounded to the nearest ten thousandth)
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The square is divided into 3 parts.
Lorico [155]
1/3= 5/15
2/5= 6/15

5/15 + 6/15 = 11/15

15/15 - 11/15 = 4/15

Part C= 4/15
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Which list of angle measures could be the angle measures of a triangle?
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Hello there! So the answer would be D: 35 degrees, 60 degrees and 85 degrees. We know this because angles in a triangle sum to 180 degrees. By simply adding each angle up, we can confirm that 35 + 60 + 85 = 180. :)
8 0
3 years ago
Given: m∠A + m∠B = m∠B + m∠C Prove: m∠C = m∠A
mel-nik [20]

Answer:

See below.

Step-by-step explanation:

m∠A + m∠B = m∠B + m∠C

Use the subtraction property of equality to subtract m<B from both sides of the equation.

m∠A + m∠B - m<B = m∠B - m<B + m∠C

m∠A = m∠C

8 0
3 years ago
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Use the Chain Rule to find the indicated partial derivatives. u = x2 + yz, x = pr cos(θ), y = pr sin(θ), z = p + r; (partial u)/
devlian [24]

u(x,y,z)=x^2+yz

\begin{cases}x(p,r,\theta)=pr\cos\theta\\y(p,r,\theta)=pr\sin\theta\\z(p,r,\theta)=p+r\end{cases}

At the point (p,r,\theta)=(2,2,0), we have

\begin{cases}x(2,2,0)=4\\y(2,2,0)=0\\z(2,2,0)=4\end{cases}

Denote by f_x:=\dfrac{\partial f}{\partial x} the partial derivative of a function f with respect to the variable x. We have

\begin{cases}u_x=2x\\u_y=z\\u_z=y\end{cases}

The Jacobian is

\begin{bmatrix}x_p&x_r&x_\theta\\y_p&y_r&y_\theta\\z_p&z_r&z_\theta\end{bmatrix}=\begin{bmatrix}r\cos\theta&p\cos\theta&-pr\sin\theta\\r\sin\theta&p\sin\theta&pr\cos\theta\\1&1&0\end{bmatrix}

By the chain rule,

u_p=u_xx_p+u_yy_p+u_zz_p=2xr\cos\theta+zr\sin\theta+y

u_p(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_p(2,2,0)=16}

u_r=u_xx_r+u_yy_r+u_zz_r=2xp\cos\theta+zp\sin\theta+y

u_r(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_r(2,2,0)=16}

u_\theta=u_xx_\theta+u_yy_\theta+u_zz_\theta=-2xpr\sin\theta+zpr\cos\theta

u_\theta(2,2,0)=-2\cdot4\cdot2\cdot2\sin0+4\cdot2\cdot2\cos0\implies\boxed{u_\theta(2,2,0)=16}

7 0
3 years ago
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