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RideAnS [48]
3 years ago
6

I have no clue what to do please help

Mathematics
1 answer:
Alborosie3 years ago
8 0
The easiest way to solve this is to convert all of the values to a decimal value, and then order the numbers as you normally would.


1/5=0.2
-4.06
10/5=2
-4.30

Now that we know the decimal values, we can simply place them from least to greatest. -4.30, -4.06, 1/5, 10/5 is the correct order.
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I need help fast. 8th grade multiple question. (I added photos)
n200080 [17]

Answer:

C is the answer

Step-by-step explanation:

5 0
3 years ago
What is the equation of the line that has a slope of -4 and passes through the point (2, 3)?
rosijanka [135]

Substituting into point-slope form,

y-3=-4(x-2)\\\\y-3=-4x+8\\\\\boxed{y=-4x+11}

7 0
2 years ago
Mr.Pham wrote 2.619.Cristy says it is two and six hundred nineteen thousandths.Amy says its 2 ones 6 tenths 1 hundredths and 9 t
Naddika [18.5K]
Cristy is right because after the decimal point it starts with the tenths place not the ones
4 0
3 years ago
Read 2 more answers
1. Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise. What
Reil [10]

Answer: A'(3,2),  B'(0,1)  and C'(-4, -5).

Step-by-step explanation:

When we rotate (a,b) 90 degrees clockwise, the new point will be (b,-a).

i.e. rotation rule for 90 degrees clockwise : (x,y) → (y,-x)

Given: Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise.

Then, the new image points for triangle A'B'C' will be :

A(-2,3) → A'(3,-(-2)) =A'(3,2)

B(-1,0)→ B'(0,-(-1)) = B'(0,1)

C(5,-4) → C'(-4, -5)

Hence, the new image points for triangle A'B'C' are A'(3,2),  B'(0,1)  and C'(-4, -5).

6 0
3 years ago
What is the solution to -4(8 – 3x) >_ 6x – 8?
Vsevolod [243]

Answer:

x ≥ 4

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define inequality</u>

-4(8 - 3x) ≥ 6x - 8

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -4:                              -32 + 12x ≥ 6x - 8
  2. Subtract 6x on both sides:        -32 + 6x ≥ -8
  3. Add 32 on both sides:              6x ≥ 24
  4. Divide 6 on both sides:             x ≥ 4

Here we see that <em>x</em> can be any value greater than or equal to 4.

3 0
3 years ago
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