Find the inverse function of h(x) = - 2/3x + 6. h -1(x) = -x + 9 h -1(x) = -x - 6 h -1(x) = -x + 9 h -1(x) = -x

Explain how you would find the sum 46+7

worty [1.4K]

1. You would set them up:46+7

2. Next you would do 6+7 which equals 13

3. You would then bring down the 4

4. And last you get the answer:53

Hope this helped you!

5 0

3 years ago

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Find all the zeroes of the polynomial function f(x)=x^3-5x^2+6x-30 using synthetic division.

WITCHER [35]

Write the coeeficientes of the polynomial in order:

| 1   - 5   6   - 30
|
|
|
------------------------

After some trials you probe with 5

   | 1   - 5    6     - 30
   |
   |
5 |        5      0       30
-----------------------------
   1    0      6        0 <---- residue

Given that the residue is 0, 5 is a root.

The quotient is x^2 + 6 = 0, which does not have a real root.

Therefore, 5 is the only root. You can prove it by solving the polynomial x^2 + 6 = 0.

3 0

3 years ago

Holly checked her answer to a division problem by estimating the quotient. Which is the best estimation of the quotient?

Andre45 [30]

Answer: 4

Try just dividing 23/5 and you’d get 4 something. But since 5.97 is close to 6 you can also mentally divide 23/6 and get 3something (it’d be really close to 4)

5 0

3 years ago

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How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago

BRAINLIEST!!!!!!!!!!!!!

qwelly [4]

6/8

This is because tan is opposite over adjacent

6 is opp of A, and 8 is adjacent A

8 0

3 years ago

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Find the inverse function of h(x) = - 2/3x + 6. h -1(x) = -x + 9 h -1(x) = -x - 6 h -1(x) = -x + 9 h -1(x) = -x - 6