Answer:
a) 20<h≤30.
b) 26.17 hrs
Step-by-step explanation:
The missing table is shown in attachment.
Part a)
We need to find the class interval that contains the median.
The total frequency is

The median class corresponds to half

That is the 15th value.
We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.
2+8+9=19
This corresponds to the class interval 20<h≤30.
Adding from the bottom also gives the same result.
Therefore the median class is 20<h≤30.
b) Since this is a grouped data we use the midpoint to represent the class.
The median is given by :




Theres a website called spades (or something like that) if you go on it look for your math text book and it will have the answers for you
Answer: n > 
Step-by-step explanation:
1. So, to understand this you need to understand that the opposite of 11 is -11.
2. Use the formula 3n+12>-11.
3. Subtract 12 from both sides (3n>-23)
4. Divide by 3 on both sides. (n>
)
5. You can go a step further and simplify into -7
.
6. n > 
Answer:
3
Step-by-step explanation:
Because 30 divided by 5 =6 which is the miles so divide 15 by 5 and the minutes are 6 so 6x5 so 3
Answer:
{ x | -7 ≤ x ≤ 4 }
Step-by-step explanation: