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scoundrel [369]
3 years ago
11

Log4 20 - log4 45 + log4 144

Mathematics
2 answers:
Anton [14]3 years ago
6 0
Do you understand how to do this one ?

Olin [163]3 years ago
3 0
The answer is 3.......
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Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Zielflug [23.3K]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S.

The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

  • A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

  • B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

  • C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

e. List the outcomes in A ∩ C

A ∩ C is an intersection between the event A and C, this means that there must be outcomes that are shared by both events.

Possible outcomes for A: S={DDD, EEE, FFF}

Possible outcomes for C: S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

As you can see there is only one possible outcome shared by these two events. So the possible outcomes for A ∩ C are:

S= {DDD}

f. List the outcomes in A U B

A U B is the union between these two events, to see what outcomes this union has you have to add every outcome of A plus every outcome of B minus the possible outcomes that A and B share:

Possible outcomes for A: S={DDD, EEE, FFF}

Possible outcomes of B: S={DEF, DFE, EDF, EFD, FDE, FED}

The possible outcomes for A U B are:

S={DDD, EEE, FFF, DEF, DFE, EDF, EFD, FDE, FED, EEF, EDF, EFD, }

g. List the outcomes in A ∩ c

c is the complementary event of C, it could also be symbolized as C^c

If C: "At least two parts are conforming" then its complemental event will be

  • C^c: At most one part is conforming"

This means that one or none parts are conforming, and it's possible outcomes are:

S= {DEF, DFE, DEE, DFF, EDE, EEE, EFE, EED, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FEE}

Possible outcomes for A: S={DDD, EEE, FFF}

As you see there are two events on "A" that also appear in the definition of "C^c"

The possible outcomes for A ∩ C^c are:

S= {EEE, FFF}

h. List the outcomes in Ac ∩ C

Ac is the complementary event of A, also symbolized as A^c

If A: "All the parts fall into the same category", then its complemental event will be

  • A^c: "Not all the parts fall into the same category"

and its possible outcomes are the remaining 24 occurrences:

S={DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFE, FFD, FDE, FED, FDD, FEE}

Possible outcomes for C: S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

As you can see the events A^c and C share 6 occurrences in common, so the possible outcomes for the intersection will be:

S= {DED, DFD, DDE, DDF , EDD, FDD}

i. Are events A and C mutually exclusive? Explain.

Two events are mutually exclusive when the occurrence of one of them keeps the other from occurring, i.e. it can happen one or the other but not both.

A and C are not mutually exclusive since the three pieces may have the same category, "D: conforming" and at least two of them to be conforming "DD-" at the same time in the occurrence "DDD" and mutually exclusive events never happen at the same time.

ii. Are events B and C mutually exclusive? Explain.

B and C are mutually exclusive, you can easily see this if you compare the possible outcomes of both events:

Possible outcomes of B: S={DEF, DFE, EDF, EFD, FDE, FED}

Possible outcomes for C: S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

There are no shared elements by these events. This means that if you were to take three pieces randomly sampled in one day and fit the definition of B, then they will not fir the definition of C and vice versa.

I hope it helps!

4 0
3 years ago
To increase an amount by 85% what single multiplier would i need to use?
Brrunno [24]
The answer is 1.85

To figure this out, think about what we want. We want our original number plus 85% of the original number. The 1 part will give you back your original number, and the 0.85 part will add 85%.
3 0
4 years ago
Find an equation of the line through (4,6) and parallel to y=3x+4
Ronch [10]

Hello!

To find the equation of line that passes through (4, 6) and is parallel to y = 3x + 4, we need to use the slope of the given line, and also to find the y-intercept. We use the same slope of the old equation to make the new equation because if two lines are parallel, then their slopes are <u>always equivalent</u> to one another.

To find the equation, we need to use slope-intercept form, which is written as y = mx + b, where m is the slope and b is the y-intercept.

y = 3x + b (substitute the given ordered pair into the equation)

6 = 3(4) + b (simplify - multiply)

6 = 12 + b (subtract 12 from btoh sides)

-6 = b

Therefore, the equation of the line that passes through (4, 6) and is also parallel to y = 3x + 4, is y = 3x - 6.

6 0
3 years ago
PLEASE HELP ASAP
Zanzabum

Answer:

C.) I x - 1 I + 3

Step-by-step explanation:

Since the bottom of the line is 3 units up, the equation should have "+ 3". Since the bottom of the line is one unit to the right, the equation should have "x - 1"

3 0
3 years ago
Becky and luke bought the same kind of pencils and erasers . Becky spent $1.45 for 2 pencils and 3 erasers . Luke spent $2.65 fo
ivann1987 [24]

Answer: the cost of each pencil is $0.5

the cost of each eraser is $0.15

Step-by-step explanation:

Let x represent the cost of one pencil.

Let y represent the cost of one eraser.

Becky spent $1.45 for 2 pencils and 3 erasers. This means that

2x + 3y = 1.45- - - - - - - - - -1

Luke spent $2.65 for 5 pencils and 1 eraser. This means that

5x + y = 2.65- - - - - - - - - -2

Multiplying equation 1 by 1 and equation 2 by 3, it becomes

2x + 3y = 1.45

15x + 3y = 7.95

Subtracting, it becomes

- 13x = - 6.5

x = - 6.5/- 13

x = 0.5

Substituting x = 0.5 into equation 2, it becomes

5 × 0.5 + y = 2.65

2.5 + y = 2.65

y = 2.65 - 2.5

y = 0.15

6 0
3 years ago
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