Write a positive or negative integer that represents the situation.

What is the remaining number in a percent problem called

velikii [3]

I think it is called the multiplier.

5 0

3 years ago

Help me pleaseeeeeeeeeeeeee

Mashcka [7]

I am pretty sure the answer is H

5 0

3 years ago

I need to find the median ,mean,mode,range,and

Makovka662 [10]

Median: 23.5
12 and 35 are in the middle so you add them and divide by 2, leaving you
23.5 as your median.
Mean: 41.3
Add all numbers together and divide the sum by the number of numbers added. So all numbers added together equals 413. Divide by ten the nuber of numbers added. 413/10 equals 41.3.
Mode: 99
The number that appears most often. In this case, 99 would be the mode.
Range: 98
The lowest number subtracted from the highest number. 99-1 equals 98.
IQR: 84.75

Hope this helped! :)

8 0

3 years ago

Read 2 more answers

948÷ 10 to the 3rd power

Arturiano [62]

948/10 = 94.8^3 = 851,971.392

5 0

2 years ago

Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h

irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = population proportion.

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, $H_0$ : p = 0.70 {means that the population proportion is equal to 0.70}

Alternate Hypothesis, $H_A$ : p < 0.70 {means that the population proportion is less than 0.70}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.63

n = sample of observations = 100

So, the test statistics = $\frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }$

= -1.528

The value of z-test statistics is -1.528.

Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

4 0

3 years ago