Basically, Benedict's test identifies the existence of aldehydes and alpha-hydroxy-ketones, also by hemiacetal, as well as those that take place in specific ketoses. Therefore, it is an alpha-hydroxy-ketone even if the ketose fructose is not strictly a reducing sugar, and provides a positive test since it is transformed into the mannose and aldoses glucose by the base inside the reagent.
Answer:
x = 9/25, y = 7/25, z = 4/25
Explanation:
step 1: solve for y in first equation to use substitution
y = -2x + 1
step 2: insert into second equation to eliminate y variable and work with two variables
3(-2x+1) + z = 1 (now distribute)
-6x + 3 + z = 1 (bring over the -3)
-6x + z = -2
step 3: now left with -6x + z = -2 and x + 4z = 1, so eliminate z
-6x + z = -2 (multiply by 4)
4(-6x + z = -2)
-24x + 4z = -8
-
x + 4z = 1 (brought down third equation)
-25x = -9
x = 9/25
then just plug in x into the third equation to solve for z, followed by plugging it into the first equation to solve for y. you should end with y = 7/25 and z = 4/25
23,000. You would just subtract the liabilities.
100m runner (don’t mind this i need it to be 20 characters long)
