Question

Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...

Answer 1

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

$a_1=-36$

now, we can find common ratio

$r=\frac{6}{-36}$

$r=-\frac{1}{6}$

now, we can find nth term

$a_n=a_1(r)^{n-1}$

now, we can plug values

and we get

$a_n=36(-\frac{1}{6})^{n-1}$

now, we can find 5th term , 6th term, 7th term

fifth term:

$a_5=36(-\frac{1}{6})^{4}$

$a_5=\frac{1}{36}$

sixth term:

$a_6=36(-\frac{1}{6})^{5}$

$a_6=-\frac{1}{216}$

seventh term:

$a_7=36(-\frac{1}{6})^{6}$

$a_7=\frac{1}{1296}$

so, next terms are

$a_5=\frac{1}{36}$ , $a_6=-\frac{1}{216}$

, $a_7=\frac{1}{1296}$.............Answer