The average rate of change of the function, over the given interval is 2.
This question is incomplete, the complete question is:
What is the average rate of change of f(x) = 2x+10, if this function interval are x = -3 to x = 0.
<h3>What is the average rate of change over the interval?</h3>
The average rate of change of f(x) over the interval [a,b] is expressed as;
Given that;
- f(x) = 2x + 10
- Interval: [ -3, 0 ], a = -3 and b = 0
We substitute our values into the expression above.
Therefore, the average rate of change of the function, over the given interval is 2.
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Answer:
4 miss days per year
Step-by-step explanation:
Let the previous employees miss days be = x
As given, miss days now are 75% less than previous
x - 75%x = 1/365
0.25x = 1/365
x = 1 / (365 x 0.25)
x = 4/365
So, average back then could have been 4 days per 365 days
In order to be given a scholarship, a swimmer must complete the 200-meter backstroke in no more than 144 seconds.
<u><em>Explanation</em></u>
Given that the time to complete a 200-meter backstroke swim for female competitive swimmers is normally distributed with a mean μ = 141 seconds and a standard deviation σ = 7 seconds
The fastest 6% of female swimmers in the nation are offered college scholarships. So, the probability will be 0.06
According to the normal distribution table, the z-score for probability of 0.06 is 0.5239
Now using z-score formula z= (x- μ)/σ , we will get...
That means, <em>(in whole number)</em>
So, in order to be given a scholarship, a swimmer must complete the 200-meter backstroke in no more than 144 seconds.
Answer:
6211 c.u. ft.
Step-by-step explanation:
Answer:
The first golf ball went higher.
Step-by-step explanation:
The equation representing the height (in feet) of a golf ball t seconds after it is hit is:
And the graph represents the height of a second golf ball t seconds after it is hit.
From the graph it can be seen that the second ball reaches its maximum height, i.e. 100 feet, after 2.5 seconds.
Compute the height of the first ball after 2.5 seconds as follows:
After 2.5 seconds the first ball reaches a height of 140 feet.
This height may or may not be the maximum height.
But for the same time, the first ball goes higher that the second ball.
Thus, the first golf ball went higher.