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laila [671]
2 years ago
15

The radius of a circular rug is 4 feet. How much ribbing will you need to buy to go around the rug? Use 3 for i.

Mathematics
2 answers:
Maslowich2 years ago
5 0

Answer:

dd

Step-by-step explanation:

dd

worty [1.4K]2 years ago
5 0
D because that’s the more correct answer trust
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Evaluate <br> g(4): g(x)=8x^2+9x-7<br><br> A. 121<br> B. 135<br> C. 154<br> D. 157
inn [45]
The answer is:  [D]:  " 157" .
________________________________________________________
Explanation:
______________________________________________________

 g(x) = 8x² + 9x − 7 ;

 g(4) = 8(4²) + 9(4) <span>− 7 ;
</span>
        = 8(4*4) + 36 <span>− 7 ;
</span>
        = 8(16) + 36 <span>− 7 ;
</span>
        = 128 + 36 <span>− 7 ;
</span>
        = 164 − 7 ;

       =  <span>157 .</span>
_______________________________________________________
The answer is:  [D]:  " 157" .
_______________________________________________________
7 0
3 years ago
Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.​
sergij07 [2.7K]

Answer:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

Step-by-step explanation:

Given

8x^{-10}y^6 - 2x^2y^{-8}

Required

Simplify

Rewrite as:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}

Take LCM

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}

Apply law of indices

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

8 0
3 years ago
What is the quotient when 72 is divided by 8
DanielleElmas [232]
72 divided by 8 is 9 :)
6 0
3 years ago
Read 2 more answers
Anna's car requires 5 1/2 gallons of gasoline to make 4 round trips to work and back. If her car can travel 24 miles per gallon
marysya [2.9K]

Answer:

33 miles

Step-by-step explanation:

5.5÷4= 1.375 gal per round

1.375×24= 33 miles

4 0
3 years ago
Order these number (smallest to largest)<br><br><br> 35.6 0.356 35.63 3.65 356.06 356.6
Alenkinab [10]

Answer: 0.356, 3.65, 35.6, 35.63, 356.06, 356.6

Step-by-step explanation:

8 0
3 years ago
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