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Bad White [126]
2 years ago
9

Drag each tile to the correct box.

Mathematics
1 answer:
harina [27]2 years ago
7 0

Answer:

its c because the bios and the text but in th e rec below the part ya ya sheeeeesh

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George invited 65 students in his school to volunteer at a charity race. 39 of the students signed up to volunteer. What percent
mr Goodwill [35]

Answer:

60%

Step-by-step explanation:

Divide the amount of people who showed up by the total invited...

39/65 = 0.6

To convert a decimal to a percent, multiply the decimal by 100%...

0.6(100%) = 60%

8 0
3 years ago
Can someone help me?
AveGali [126]
A=-112 bcs -216 ft is down from sea level and -104 is also down from sea level bcs both values are in minus but -104 is higher than other so you can minus it from -216 the difference is the answer
b=-109
4 0
3 years ago
A football team of 11 players has a mean height of 1.83m. One player is injured and is replaced by a player of height 1.85m. The
trapecia [35]

Answer:

As the average has increased the height of the new player must be more then the height of the player which was injured.

The difference between the previous average and the new average is 0.01 m.

Therefore the average is increased by 0.01 m.

Therefore the total height of all the players is increased by 0.01*11=0.11 m

Therefore as the increase in the total height is made by the player with height 1.85 m,the height of the player who was injured is 1.85–0.11=1.74 m

The height of the player who was injured is 1.74 m

Step-by-step explanation:

7 0
1 year ago
Simplify the expression. (–1 – 6i) + (–3 + 3i)
Alisiya [41]

Answer:B

Step-by-step explanation:

4 0
2 years ago
Lemons tastes sour to some people. This sourness is inherited through the TAS2R38 gene. About 65% of the population has this gen
Minchanka [31]

Answer:

We are given:

\hat{p}=0.65

Margin of error E=0.02

Confidence level = 0.99

We need to find the sample size to estimate the proportion of people who carry the TAS2R388 gene.

The formula for finding the sample size is:

n=\hat{p} (1-\hat{p})\left (\frac{z_{\frac{0.01}{2}}}{E} \right )^{2}

Where:

z_{\frac{0.01}{2}}=2.576 is the critical value at 0.01 significance level.

Therefore, the required sample size is:

n=0.65(1-0.65) \left(\frac{2.576}{0.02} \right)^{2}

      =0.2275 \times 16589.44

      =3774.1 \approx 3774

Therefore, the required sample size is 3774


3 0
3 years ago
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