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Montano1993 [528]
3 years ago
9

Choose the true statement about the graph of 3x ≥ 6.. closed circle on 2 and all numbers to the right shaded. closed circle on 2

and all numbers to the left shaded. open circle on 2 and all numbers to the right shaded. open circle on 2 and all numbers to the left shaded

Mathematics
2 answers:
mihalych1998 [28]3 years ago
8 0

Answer:

A closed circle on 2 and all numbers to the right shaded.

Step-by-step explanation:

We have to graph the linear inequality with a equality sign in terms of single variable 'x' which is given as:

                     3x\geq 6

Now when we divide both side of the inequality by 3 we obtain the resulting inequality with a equality sign as:

                         x\geq2

Hence, the range of the inequality is:

           [2,\infty)

i.e. we get a graph as:

closed circle on 2 and all numbers to the right shaded.

Karolina [17]3 years ago
3 0
"Closed circle on 2 and all numbers to the right shaded" is the one statement among the following choices given in the question that is true <span>about the graph of 3x ≥ 6. The correct option among all the options that are given in the question is the first option. I hope that this is the answer that has come to your help.</span>
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(-y+5•3)+7.2y-9)=6.2y+n
kramer
(-y+5x3)+(7.2y-9)=6.2y+n
(-y+15)+(7.2y-9)=6.2y+n
since you're adding the two parentheses, you don't need to have them there
-y+15+7.2y-9=6.2y+n
7.2y-y +15-9 =6.2y+n
6.2y + 6 =6.2y+n
6.2y - 6.2y -n = -6
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3 0
3 years ago
​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$17 comma 90017,900
Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-17900=\frac{20300-17900}{4-1}(x-1)

y-17900=\frac{2400}{3}(x-1)

y-17900=800(x-1)

y-17900=800x-800

Add 17900 on both sides.

y=800x-800+17900

y=800x+17100

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

30700=800x+17100

Subtract 17100 from both sides.

30700-17100=800x

13600=800x

Divide both sides by 800.

\frac{13600}{800}=x

17=x

Therefore, in 17th year his income was $30,700.

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