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meriva
3 years ago
8

a student's work to distribute and simplify a radical is shown below. Select the statement which best applies to the sample math

ematical work. given (-5√20+√3)*(2+√3), i first distribute to get the expression -10√20-5√60+2√3+√9, which i can simplify to -40√5-20√15+2√3+3 for an answer. a. the student did not properly distribute the radicals b. the student overlooked combining one or more of the radical terms c. the student did not properly simplify all radicals d. the work shown above is correct
Mathematics
2 answers:
weqwewe [10]3 years ago
4 0
C), radicals siplified incorrectly
tankabanditka [31]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that a student's work to distribute and simplify a radical is shown below.

Given

(-5√20+√3)*(2+√3)

The next step of distribution is

-5√60+2√3+√9 is done correctly.

Next step is

-40√5-20√15+2√3+3

I term = -10√20=-20√5

Correct answer is

Hence c) the student did not properly simplify all radicals

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Use the commutative property to solve for n<br> 98,551+2,851=2,841+n<br> n=
dezoksy [38]
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How many arrangements of three letter can be formed from the letters of the word MATH if anyletter will not be used more than on
Mariulka [41]

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7 0
1 year ago
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Alika [10]
1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).

2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.

4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.

5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)

Hope this helped :) Have a great day 
8 0
3 years ago
Read 2 more answers
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