Answer:
a. See Attachment 1
b. 
c. 
d. 
Step-by-step explanation:
Calculating PT
To calculate PT, we need to get distance OT and OP
Calculating OT;
We have to consider angle 50, distance OH and distance OT
The relationship between these parameters is;

Multiply both sides by 20





Calculating OP;
We have to consider angle 30, distance OH and distance OP
The relationship between these parameters is;

Multiply both sides by 20








(Approximated)
--------------------------------------------------------
Calculating the distance between H and the top of the tower
This is represented by HT
HT can be calculated using Pythagoras theorem

Substitute 20 for OH and 



Take Square Root of both sides

<em>(Approximated)</em>
--------------------------------------------------------
Calculating the position of H
This is represented by OH
See Attachment 2
We have to consider angle 50, distance OH and distance OT
The relationship between these parameters is;

Multiply both sides by OT



Substitute 


<em> (Approximated)</em>