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Wewaii [24]
4 years ago
7

Evaluate the expression when c=4. 4c−7.8 = ???????

Mathematics
2 answers:
vesna_86 [32]4 years ago
7 0

Answer:

8.2

Step-by-step explanation:

4(4)-7.8

ivanzaharov [21]4 years ago
7 0

So if c=4, the equation will be (4 × 4) - 7.8. Use PEMDAS (parenthesis, exponents, multiplication, division, addition, & subtraction) to solve.

4 × 4 = 16

16 - 7.8 = 8.2

<h2>Answer:</h2>

4(c) - 7.8 when c = 4 equals 8.2.

I hope this helps :)

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3 years ago
Explain how you found your answer
bogdanovich [222]

Answer:

29°

Step-by-step explanation:

151° + a=180°

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5 0
3 years ago
What is the value of ?<br> –34<br> –2<br> 10<br> 34
Zolol [24]

Answer:

-2

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7 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through the points (2,4)and (6,12)
jok3333 [9.3K]

Answer:

2

Step-by-step explanation:

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3 0
3 years ago
An insurance company divides its policyholders into low-risk and high-risk classes. 60% were in the low-risk class and 40% in th
AleksAgata [21]

Answer:

a). 0.294

b) 0.11

Step-by-step explanation:

From the given information:

the probability of the low risk = 0.60

the probability of the high risk = 0.40

let C_o represent no claim

let C_1 represent 1 claim

let C_2 represent 2 claim :

For low risk;

so, C_o  = (0.80 * 0.60 = 0.48),  C_1 =  (0.15* 0.60=0.09),   C_2 = (0.05 *  0.60=0.03)

For high risk:

C_o  = (0.50 *  0.40 = 0.2),  C_1 =  (0.30 *  0.40 = 0.12) ,   C_2 = ( 0.20 *  0.40 = 0.08)

Therefore:

a),  the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:

P(H|C_o) = \dfrac{P(H \cap C_o)}{P(C_o)}

P(H|C_o) = \dfrac{(0.2)}{(0.48+0.2)}

P(H|C_o) = \dfrac{(0.2)}{(0.68)}

P(H|C_o) = 0.294

b) What is the probability that a randomly selected policyholder filed two claims?

the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08

= 0.11

7 0
3 years ago
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