Answer:
A and C on Edge
Step-by-step explanation:
Just completed the assignment
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at </span></span> A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36
Answer:
3. 50.27 inches squared
4. 113.1 km squared
Step-by-step explanation:
3. A=πr^2
π*16
4. A=πr^2
π*36
Have a good day :)
Subtract y
3x - y + 5 = 0
u(x) = -2x², v(x)= 1/x
(u o v)(x) = u(v(x)) = -2(1/x)²= -2/x²
We can see that domain for x is going to bee all real numbers except 0. From the equation above we can see that graph of the function (u o v)(x) = -2/x² has horizontal asymptote y=0, because degree of numerator is less than degree of denominator ( (u o v)(x) = -2x⁰/x² ).
x² is always going to be positive, so range is going to be all negative numbers.
y<0, or y∈(0,-∞)