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sweet-ann [11.9K]
3 years ago
12

What’s the area of this question

Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:

111 mi

Step-by-step explanation:

Hope this helps. Have a nice night!

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Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
Harman [31]

Formula for the perimeter of a quarter circle: C = ((pi x 2r) / 4) + 2r

C = ((3.14 x 18) / 4) + 18

C = (56.52 / 4) + 18

C = 14.13 + 18

C = 32.13 miles

Hope this helps! :)

5 0
4 years ago
9. If f(x)=x². g(x)=2x-1. and h(x) =find the following.
postnew [5]

Answer:

Please see the attached picture ! :D

-------- HappY LearninG <3 ----------

8 0
2 years ago
Find the value of x if mPYA 12x 20 and m LPLA 110O 220O 240O 20O 40
romanna [79]
M<PLA = 1/2 m PYA
110 = 1/2 (12x - 20)
12x - 20 = 220
12x = 220 + 20 = 240
x = 240 / 12 = 20
4 0
4 years ago
What is the measure of Arc BA? An explanation would be much appreciated.
yKpoI14uk [10]

Answer:

m<BA = 180degrees

Step-by-step explanation:

First you must know that measure of <BA is 180 degrees and m<CD = m<BA

Since <CD = 16z - 12, hence;

180 = 16z - 12

16z = 180++12

16z = 192

z = 192/16

z = 12

Get <BA

m<BA = 16z - 12

m<BA = 16(12) - 12

m<BA = 192 - 12

m<BA = 180degrees

8 0
3 years ago
Someone please help or i’ll be failing geometry this year
Vlad [161]

Step-by-step explanation:

I don't know what constructions you were taught.

a "similar" triangle is a triangle with exactly the same angles as the other triangle, but the lengths of all sides are stretched or shortened by the same scaling factor f.

by saying 1:2 she means the second triangle should have sides with twice the lengths of the first triangle (f=2).

and the extra challenge - same basic thing. she allows you to pick one of the two triangles as reference. and then you need to draw a third triangle (again with the same angles) with the side lengths extended by the scaling factor f of 4/3.

I would draw the triangles right on top of each other with the same starting corner (let's call it A) for all 3.

we would get the triangles ABC, AMN and AXY.

the points B and C would be then halfway on AM and AN.

and M and N would then a bit before X and Y on AX and AY.

the beauty is, you only need to construct 2 sides of every new triangle down to the new endpoints. the third side is automatically scaled correctly, and you only need to connect these new endpoints.

let's assume you draw a triangle (just very simple) ABC with all side lengths being 3. so, AB=3, AC=3, BC=3.

now you draw AMN by extending AB and AC to a side length of 6 (f=2) creating M and N, and you connect M and N.

and then you can create the third triangle AXY by extending AM and AN by a factor of 4/3 to side lengths of 8 (4/3 × 6 = 8) creating new end points X and Y. and you connect X and Y.

and that is it. all 3 triangles are similar (the same angles), and all sides of a triangle have the same length ratio to the sides of the other triangle(s).

4 0
3 years ago
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