Round to the nearest cent. 5. $406.439

Mathematics

1 answer:

boyakko [2]3 years ago

7 0

Answer:

406.4

Step-by-step explanation:

When rounding you only look at the number you're rounding and the one before it. In this case it would be the 4 and 3 after the decimal since we're rounding to the nearest cent. If the numbers before the one you're rounding are 0-4 then you leave the number the same. If the numbers are between 5-9 then you add one to the number. Since the number before 4 is between 0-4 you leave it as 4. But if it was between 5-9 then you'd change the 4 to 5.

You might be interested in

Which statement is true?

melamori03 [73]

Answer:

c ???

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please HELP! I DON'T KNOW HOW CAN I SOLVE THIS

Wewaii [24]

Answer:

Step-by-step explanation:

The Pythagorean Theorem:

$leg^2+leg^2=hypotenuse^2\to a^2+b^2=c^2$

$41.\\\\a=1,\ b=1,\ c=x\\\\x^2=1^2+1^2\\\\x^2=1+1\\\\x^2=2\to x=\sqrt2$

$42.\\a=1, b=2,\ c=x\\\\x^2=1^2+2^2\\\\x^2=1+4\\\\x^2=5\to x=\sqrt5$

$43.\\a=3,\ b=x,\ c=5\\\\3^2+x^2=5^2\\\\9+x^2=25\qquad\text{subtract 9 from both sides}\\\\x^2=16\to x=\sqrt{16}\to x=4$

$44.\\\\a=4,\ b=x,\ c=8\\\\4^2+x^2=8^2\\\\16+x^2=64\qquad\text{subtract 16 from both sides}\\\\x^2=48\to x=\sqrt{48}\\\\x=\sqrt{16\cdot3}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\x=\sqrt{16}\cdot\sqrt3\\\\x=4\sqrt3$