Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.

![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)


So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Answer:
Step-by-step explanation:
there are infinite numbers between 2 and 3 having average=2.5
2.49,2.51
2.48,2.52
2.47,2.53
2.46,2.54
.................
2.491,2.509
2.492,2.508
2.493,2.507
......................
Answer:
25
Step-by-step explanation:
dababy go yeayea
Answer:
Percent change = 5.4%
Step-by-step explanation:
Given:
Number of students voted last year = 762
Number of students voted this year = 721
Change in the number of students who voted from last year to this year is given by the difference of their number. This gives,
Change in the number of students that voted = 762 - 721 = 41
Now, percentage change in the number of students that voted is given as:

Therefore, the percent change in the number of students that voted is 5.4%.