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3 years ago

Help please!! 10 points <3

Mathematics

2 answers:

nikitadnepr [17]3 years ago

8 0

X=5 exactly like that person said.

tangare [24]3 years ago

5 0

Answer:

x = 5

Step-by-step explanation:

15 / 3 =5

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What is the length of side AC of the triangle?<br><br> Enter your answers in the boxes.

inessss [21]

Answer:

$AC=25$

Step-by-step explanation:

From the given figure, it can be seen that ${\angle}A={\angle}C$ , thus ΔABC is an isosceles triangle.

Therefore, $AB=BC$

⇒ $5x+5=7x-1$

Solving the above equation, we get

⇒ $5x-7x=-1-5$

⇒ $-2x=-6$

⇒ $x=3$

Now, substituting the value of x in AC, we have

⇒ $AC=6x+7$

⇒ $AC=6(3)+7$

⇒ $AC=18+7$

⇒ $AC=25$

Thus, the length of the side AC of the given triangle is 25 units.

3 0

3 years ago

Answer and explain please <br> ANSWER ASAP!!!!!!!!!!!!!!!!!

vodomira [7]

Answer:

y = 1/3x + 3

Step-by-step explanation:

slope is 1/3

y intercept is 3

I hope this helps

brainliest is appreciated... :}

4 0

4 years ago

Multiply. −5m(−2m6+4m4+m−9) Express the answer in standard form.

tatuchka [14]

−5m(−2m6+4m4+m−9)

= 10m^7 - 20m^5 - 5m^2 + 45m

7 0

3 years ago

Read 2 more answers

Write the proportion 5.5 hours is to 4.5hrs as 7.5 hours in to 60hours

TEA [102]

So the proportion would go as follows

5.5. 7.5
=
4.5. 60

To solve this you just cross muliply and divide.
I hope this helps you

4 0

3 years ago

A container initially containing10 L of water in which there is 20 g of salt dissolved. A solution containing 4 g/L of salt is p

Kay [80]

Answer:

$A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196$

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by $V= 10 +t$

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

$\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}$

Because at the begin we have a concentration of 8 gr/L and would be decreasing at a rate of $\frac{A}{10+t}$

So then we can reorder the differential equation like this:

$\frac{dA}{dt} +\frac{A}{10+t} =8$

We find the solution using the integration factor:

$\mu = -\int \frac{1}{10+t} dt = -ln(10+t)$

And then the solution would be given by:

$A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})$

And if we simplify this we got:

$A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)$

And after do the integral we got:

$A= \frac{c}{10+t} +4 (10 +t)$

And using the initial condition t=0 A= 20 we have this:

$20 = \frac{c}{10} +40$

$c= -200$

So then we have this function for the solution of A:

$A= \frac{-200}{10+t} +4 (10 +t)$

And now replacinf t= 40 we got:

$A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196$

8 0

3 years ago