Answer:
=(a-b)(a^2+ab+b^2)
= a^3+a^2b+ab+ab^2-ba^2-ab^2-b^3
SIMPLIFY
=a^3+ab-b^3
Answer:
-4, -2, 0, 1, 3 <--- lowest to highest
166.7 may be the answer but the question is very confusing
<span><span>2<span>x^2</span></span>+<span><span>4x</span>y</span></span>−<span>2<span>y^<span>2
hope this helps</span></span></span>
To get the equation of the line, you need two points that belong to this line.
From the given graph, we can choose any two points: (0,-4) and (-2,0)
The general for of the linear straight line is:
y = mx + c where m is the slope and c is the y-intercept
First, we will calculate the slope using the following rule:
slope = (y2-y1) / (x2-x1)
slope (m) = (0--4) / (-2-0) = 4/-2 = -2
The equation of the line now is: y = -2x + c
Then, we will get the value of the c. To do so, we will choose any point and substitute in the equation. I will choose the point (0,-4)
y = -2x + c
-4 = -2(0) + c
c = -4
Based on the above calculations, the equation of the line is:
y = -2x - 4
