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GrogVix [38]
3 years ago
12

Robin is building a new pool to help him relax after a long night of crime fighting. The picture above shows the dimensions of t

he rectangular pool.
1. What is the area of the pool?

2. What is the perimeter of the pool?

3. What would the area of the pool be if x=10?

Mathematics
2 answers:
vodka [1.7K]3 years ago
7 0
1. 2x^2 + 12x + 16

2. 6x + 16

3. 336
ycow [4]3 years ago
7 0
1. the area is 4
2. the perimeter is 8
3. 20 by 10
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What is the volume of the prism?<br> ft3<br> 1<br> 12 ft<br> 6 ft<br> 8 ft
zavuch27 [327]

V=lwh

V=8×12×6=576 ft³

Answer: V=576 ft³

7 0
3 years ago
Can someone please tell me if this is correct if it’s not can u tell me what’s the correct answer
bearhunter [10]

Answer:

2. option D and 3. option A

Step-by-step explanation:

2. 7 + y = 30

<u>7 - 7</u> + y = <u>30 - 7</u>

y = 23

3. w - 32 = 55

w <u>-</u><u> </u><u>32</u><u> </u><u>+</u><u> </u><u>32</u> = <u>55</u><u> </u><u>-</u><u> </u><u>32</u>

w = 87

Basically the answers you choose are right. Hope this helps, thank you :) !!

8 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
What’s the correct answer for this?
VMariaS [17]

Answer:

Second option is the correct answer

(x+11)^2+(y+6)^2 = 324

Step-by-step explanation:

x^{2} +12y+22x+y^2-167=0\\x^{2}+22x +y^2 +12y-167=0\\(x^{2}+22x +121)-121 +(y^2 +12y+36)-36-167=0\\(x+11)^2+(y+6)^2-324 = 0\\\huge\red{\boxed{(x+11)^2+(y+6)^2 = 324}}\\

5 0
3 years ago
Read 2 more answers
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
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