B, The greatest common factor for 55 and 100 is 5.Divide 55 by 5 and you get 11.Divide 100 by 5 and you get 20.In its simplest form, the fraction 55/100 equals 11/20.
Answer:
a) 0.8836
b) 0.7339
c) 0.2342
Step-by-step explanation:
Books classified as fiction = 94% or 0.94 probability
Books classified as non-fiction = 1 - 0.94 = 0.06
a) for two books, we get: 0.94 * 0.94 = 0.8836 Probability
b) The probability that all five books are fiction is: 0.94^5
This equals 0.7339 Probability
c) Probability that one books is non-fiction, while the other 4 are fiction is determined in the following way:
Probability of non-fiction * probability of fiction^(number of books)
0.06 * 0.94^4 = 0.0468
This does not account for the order at which the non-fiction book shows up. Such as the non-fiction book being the first book picked, or in another case - the non-fiction book being the last picked.
Since there are 5 ways this could occur, the total probability will be calculated as shown: 0.0468 * 5 = 0.2342 Probability
Answer:
Step-by-step explanation:
as said in my comment
A: (3x-2)X(x+1)
B: substitute 3 in(if m=meters),
(3x3-2)
9-2
7X(x+1)
3+1
4
7X4
28
Answer:
½ sec²(x) + ln(|cos(x)|) + C
Step-by-step explanation:
∫ tan³(x) dx
∫ tan²(x) tan(x) dx
∫ (sec²(x) − 1) tan(x) dx
∫ (sec²(x) tan(x) − tan(x)) dx
∫ sec²(x) tan(x) dx − ∫ tan(x) dx
For the first integral, if u = sec(x), then du = sec(x) tan(x) dx.
∫ u du = ½ u² + C
Substituting back:
½ sec²(x) + C
For the second integral, tan(x) = sin(x) / cos(x). If u = cos(x), then du = -sin(x) dx.
∫ -du / u = -ln(u) + C
Substituting back:
-ln(|cos(x)|) + C
Therefore, the total integral is:
½ sec²(x) + ln(|cos(x)|) + C
Answer:
97
Step-by-step explanation:
4^2+3(37-(2*5))
4^2+3(37-10)
4^2+3(27)
16+3(27)
16+81
=97
