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Softa [21]
3 years ago
6

You earn $10 per hour working as a manager at a grocery store. You are required to work at the grocery store at least 8 hours pe

r week. You also teach music lessons for $15 per hour. You need to earn at least $120 per week, but you do not want to wok more than 20 hours per week.
Write a system of linear inequalities that represents the situation. Use x for hours worked at the grocery store and y for hours teaching music lessons.
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
You would have to multiply 120 x 20 then divide by 8. I hope that helps you!
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Help please and thank you​
Lelu [443]

Answer: 30 posts

Step-by-step explanation:

each post is 5 feet apart and 30 x 2 + 45 x 2 = 150 which divided by 5 is 30

7 0
3 years ago
Two parts Someone please help!!!!!
aivan3 [116]

Answer:

Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x

Part two: The area of the rectangle is 8 feet² when its width is 2 feet

Step-by-step explanation:

Assume that the width of the rectangle is x

∵ The width of the rectangle = x feet

∵ The length of the rectangle is 2 ft less than three times its width

→ That means multiply the width by 3, then subtract 2 from the product

∴ The length of the rectangle = 3(x) - 2

∴ The length of the rectangle = (3x - 2) feet

∵ The area of the rectangle = length × width

∴ A(x) = (3x - 2) × x

→ Multiply each term in the bracket by x

∵ A(x) = x(3x) - x(2)

∴ A(x) = 3x² - 2x

∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x

∵ The rectangle has a width of 2 ft

∵ The width = x

∴ x = 2

→ Substitute x by 2 in A(x)

∵ A(2) = 3(2)² - 2(2)

∴ A(2) = 3(4) - 4

∴ A(2) = 12 - 4

∴ A(2) = 8

∴ The area of the rectangle is 8 feet² when its width is 2 feet

5 0
3 years ago
Can someone help me plss!!?? ​
VMariaS [17]
Answer: 1/12 || 2x-1/2=2x-1/12
5 0
4 years ago
Read 2 more answers
Can someone answer this for me?
Svetlanka [38]

Answer:

24.75

Step-by-step explanation:

divide 33.00 by 4 and multiply the sum by 3

5 0
2 years ago
Read 2 more answers
a rectangular dog kennel is to be constructed alongside a house with 60m of fencing. If the house serves as one side of the kenn
Basile [38]

Answer:

450\text{ m}^2.

Step-by-step explanation:

Let x represent side of kennel opposite to house and y represent other sides.

We have been given that a rectangular dog kennel is to be constructed alongside a house with 60 m of fencing.

Since fencing will cover 3 sides of kennel, so perimeter of kennel would be:

x+y+y=60

x+2y=60

Let us solve for x.

x+2y-2y=60-2y

x=60-2y

The area of the kennel would be product of its sides that is:

\text{Area}=x\cdot y

Now, we will substitute x=60-2y in area equation as:

A(y)=(60-2y)\cdot y

A(y)=60y-2y^2

Let us find the derivative as shown below:

A'(y)=60-4y

Now, we will set derivative equal to 0 and solve for y.

60-4y=0

60=4y

\frac{60}{4}=\frac{4y}{4}

y=15

Upon substituting y=15 in area function, we will greatest possible area.

A(y)=60y-2y^2

A(15)=60(15)-2(15)^2

A(15)=900-2(225)

A(15)=900-450

A(y)=450

Therefore, the greatest possible area that can be enclosed by 60 m of fencing is 450 square meters.

5 0
3 years ago
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