Answer: 30 posts
Step-by-step explanation:
each post is 5 feet apart and 30 x 2 + 45 x 2 = 150 which divided by 5 is 30
Answer:
Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x
Part two: The area of the rectangle is 8 feet² when its width is 2 feet
Step-by-step explanation:
Assume that the width of the rectangle is x
∵ The width of the rectangle = x feet
∵ The length of the rectangle is 2 ft less than three times its width
→ That means multiply the width by 3, then subtract 2 from the product
∴ The length of the rectangle = 3(x) - 2
∴ The length of the rectangle = (3x - 2) feet
∵ The area of the rectangle = length × width
∴ A(x) = (3x - 2) × x
→ Multiply each term in the bracket by x
∵ A(x) = x(3x) - x(2)
∴ A(x) = 3x² - 2x
∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x
∵ The rectangle has a width of 2 ft
∵ The width = x
∴ x = 2
→ Substitute x by 2 in A(x)
∵ A(2) = 3(2)² - 2(2)
∴ A(2) = 3(4) - 4
∴ A(2) = 12 - 4
∴ A(2) = 8
∴ The area of the rectangle is 8 feet² when its width is 2 feet
Answer: 1/12 || 2x-1/2=2x-1/12
Answer:
24.75
Step-by-step explanation:
divide 33.00 by 4 and multiply the sum by 3
Answer:
.
Step-by-step explanation:
Let x represent side of kennel opposite to house and y represent other sides.
We have been given that a rectangular dog kennel is to be constructed alongside a house with 60 m of fencing.
Since fencing will cover 3 sides of kennel, so perimeter of kennel would be:


Let us solve for x.


The area of the kennel would be product of its sides that is:

Now, we will substitute
in area equation as:


Let us find the derivative as shown below:

Now, we will set derivative equal to 0 and solve for y.




Upon substituting
in area function, we will greatest possible area.





Therefore, the greatest possible area that can be enclosed by 60 m of fencing is 450 square meters.