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Katyanochek1 [597]
3 years ago
7

For which interval is the average rate of change of f(x) negative?

Mathematics
2 answers:
Arisa [49]3 years ago
8 0

Answer:

C on edge

Step-by-step explanation:

Nina [5.8K]3 years ago
5 0
The Average Rate of Change<span> function describes the average rate at which one quanity is changing with respect to something else changing.
</span><span> For this case, the first thing you should do is observe the intervals for which the function decreases.
 Remember that the definition of average rate of change is given by:
</span> AVR = (f (x2) - f (x1)) / (x2-x1)&#10;
<span> For AVR to be negative, it must necessarily pass:
</span> x2\ \textgreater \  x1&#10;&#10;f (x1) \ \textgreater \  f (x2)<span>
 The interval that meets both conditions is:
 x = 0 to x = 2.5
 Answer:
 x = 0 to x = 2.5
 option 3</span>
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Step-by-step explanation:

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I’m confused on this answer anyone know it?
slamgirl [31]

Answer:

y=\frac{26}{7},\:x=-\frac{15}{7}

Step-by-step explanation:

\begin{bmatrix}4x+5y=10\\ -2x+y=8\end{bmatrix}\\\\\begin{bmatrix}-2\cdot \frac{10-5y}{4}+y=8\end{bmatrix}\\\\

-5+\frac{7y}{2}=8\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\-5\cdot \:2+\frac{7y}{2}\cdot \:2=8\cdot \:2\\-10+7y=16\\y=\frac{26}{7}\\

\mathrm{For\:}x=\frac{10-5y}{4}\\\mathrm{Subsititute\:}y=\frac{26}{7}\\x=\frac{10-5\cdot \frac{26}{7}}{4}\\\\

x=-\frac{15}{7}\\

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