Dipole-dipole interactions, and London dispersion interactions
- Frequency=v=2×10^15Hz
- Energy=E
Using planks quantum theory




Answer:
56.2÷6.02×10^23
=9.34×10^23
Explanation:
Divide the given mass of the atom by the mass of an Atom (the avogadro's constant) to find the number of atoms in the given mass.
D.) There must be an equal number of atoms of each element on both sides of the equation