First, you mix the salt and sand with water, so the salt dissolves. Next, you filter the sand out, so you have the slat water and sand separated. Then, you evaporate the water, leaving the salt behind.
1.64 L of sulfur dioxide (SO₂)
Explanation:
We have the following chemical reaction:
S (s) + O₂ (g) → SO₂ (g)
First we calculate the number of moles of sulfur (S):
number of moles = mass / molar weight
number of moles of sulfur = 2.35 / 32 = 0.0734 moles
Looking at the chemical reaction we see that 1 moles of sulfur (S) produces 1 moles of sulfur dioxide (SO₂), so 0.0734 moles of sulfur will produce 0.0734 moles of sulfur dioxide (SO₂).
To calculate the volume of sulfur dioxide (SO₂), assuming that the sulfur dioxide is behaving as an ideal gas and the we determine the gas volume under standard temperature and pressure conditions, we use the following formula:
number of moles = volume / 22.4 (L/mole)
volume = number of moles × 22.4
volume of SO₂ = 0.0734 × 22.4 = 1.64 L
Learn more about:
molar volume
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PS: I appreciate that you took the time and effort to write the chemical equation in a readable way. This makes the question to be very rare :D
Answer:
ExplanatioFirst let us compute for the molar mass of Mg(OH)2.
molar mass = 24.3 + 2 (16) + 2(1.0)
molar mass = 58.3 g/mol
So the mass is then:
mass = 3.2 mol * (58.3 g/mol)
mass = 186.56 gramsn:
