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suter [353]
2 years ago
6

During a reaction with solids generally the _______ the size of each piece, the larger the total surface area. This means ______

_ collisions and a greater chance of reaction.
A. smaller, more
B. larger, more
C. larger, less
D. smaller, less
Chemistry
1 answer:
Degger [83]2 years ago
7 0

Answer:

A

Explanation:

I'm assuming this question implies that the surface area is in relation to the volume of the pieces. In that case, the SMALLER the size of each piece, the larger the surface area. This is because more particles are able to fit into the container if they are smaller, leading to more surface area. Since more pieces can fit into the container, MORE collisions happen according to collision theory. I cannot add a link, but for a helpful analogy, look up "How To Speed Up Chemical Reactions (and get a date) - Aaron Sams.

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c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ
Umnica [9.8K]

<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

\text{moles of propane}=\frac{44g}{44g/mol}=1mole

For the reaction of combustion reaction of propane, the equation follows:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = \frac{1}{1}\times 4=4moles of water.

Now, to calculate the amount of water, we use equation 1, we get:

Molar mass of water = 18 g/mol

4mol=\frac{\text{Mass of water}}{18g/mol}

Mass of water produced = 72 grams

Hence,  72 grams of water will be produced.

6 0
3 years ago
Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and
Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%

Then,

Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%

Percent\ yield\ of\ copper\ hydroxide= 84\%

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

7 0
2 years ago
A gaseous mixture contains 5.0 moles of nitrogen and 10.0 moles of helium . What is the total pressure if the temperature is 25
jolli1 [7]

Answer:

A) 122 atm

Explanation:

PV = nRT

Solve for P --> P = nRT/V

n = 10.0 mol + 5.0 mol = 15.0 mol

R = 0.08206 L atm / mol K

T = 25 + 273 = 298 K

V = 3.0

P = (15.0)(0.08206)(298) / (3.0) = 122 atm

6 0
2 years ago
A student made this model of a carbon dioxide molecule. its has one carbon atom and two oxygen atoms what is the correct way to
ExtremeBDS [4]
The proper way to chemically write carbon dioxide is CO2
4 0
3 years ago
Read 2 more answers
Hydrobromic acid is added to a solution of lead(II) nitrate. Predict the products, and write a balanced equation for this reacti
Ber [7]

Answer:

2HBr + Pb(NO₃)₂ → PbBr₂ + 2HNO₃

Explanation:

Hydrobromic acid (HBr), reacts with lead (II) nitrate (Pb(NO₃)₂) producing Lead(II) bromide (PbBr₂) and nitric acid (HNO₃). The reaction is:

HBr + Pb(NO₃)₂ → PbBr₂ + HNO₃

This reaction is unbalanced. You can see in products 2 Bromides but in reactants just 1. And in reactants 2 NO₃ but as product just 1. Thus, you can balance the equation, thus:

<em>2HBr + Pb(NO₃)₂ → PbBr₂ + 2HNO₃</em>

And this equation is the answer of your question!

<em />

7 0
3 years ago
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