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Angelina_Jolie [31]
3 years ago
15

HURRY!!

Mathematics
1 answer:
scoundrel [369]3 years ago
4 0

Answer:

I'm sorry you got that wrong. The correct answer was R since it is staying in the same place which is called a constant line. It stays in the same place since she isn't moving, she is just standing there waiting for the cab.


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Solve for n, please i would really appreciate it :)
Lelu [443]

Answer:

2

Step-by-step explanation:

{ {a}^{b} }^{c}  =  {a}^{bc } \\ in \: this \: case \\  { ({8}^{n}) }^{3}  =  {8}^{3n}  \\ \\  {8}^{3n}  =  {8}^{6 }  \\ 3n = 6 \\ n =  \frac{6}{3}  = 2

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6. What are the extremes of the following proportion? 3⁄15 = 12⁄60 A. 3 and 60 B. 3 and 15 C. 15 and 12 D. 12 and 60
bonufazy [111]
3 and 60 are the extremes while 15 and 12 are the means. 
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4 years ago
K/4 - 5k + 1 = 1<br> please
irinina [24]

Answer:

-19k ≠ 0

No solutions

Step-by-step explanation:

k/4 - 5k + 1 = 1

4 (k/4 - 5k + 1 = 1)

k-20k + 4 = 4

-19k ≠ 0

4 0
3 years ago
Could u help me make sure its the right answer i can't get this wrong .
Black_prince [1.1K]

Answer:

12x + 6y = 102

5x - 6y = 34

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5 0
3 years ago
Read 2 more answers
After examining daily receipts over the past year, it was found that the green parrot italian restaurant has been grossing over
denpristay [2]

Complete question is;

After examining daily receipts over the past year, it was found that the green parrot italian restaurant has been grossing over $2200 a day for about 85% of it's business days. Using this as a reasonably accurate measure, find the probability that the green parrot will gross over $2200:

A. At least 5 of the next 7 business days.

B. at least 5 of the next 10 business days.

C. less than 3 of the next 5 business days.

d. Exactly 7 of the next 10 business days

e. At least 1 of the next 5 business days.

Answer:

A) P(X ≥ 5) = 0.9262

B) P(X ≥ 5) = 0.9986

C) P(X ≤ 2) = 0.0266

D) P(X = 7) = 0.1298

E) P(X ≥ 1) = 0.9999

Step-by-step explanation:

This is a binomial probability distribution problem and as such we will use the formula;

P(X = k) = C(n, k) × p^(k) × (1 - p)^(n - k)

A. At least 5 of the next 7 business days will be;

P (X ≥ 5) = P(X = 5) + P(X = 6) + P(X = 7)

P(X = 5) = C(7, 5) × 0.85^(5) × (1 - 0.85)^(7 - 5)

P(X = 5) = 0.20965

P(X = 6) = C(7, 6) × 0.85^(6) × (1 - 0.85)^(7 - 6)

P(X = 6) = 0.396

P(X = 7) = C(7, 7) × 0.85^(7) × (1 - 0.85)^(7 - 7)

P(X = 7) = 0.320577

Thus;

P(X ≥ 5) = 0.20965 + 0.396 + 0.320577

P(X ≥ 5) = 0.9262

B. Probability of at least 5 of the next 10 business days will be;

P(X ≥ 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

From online binomial calculator attached, we can see that the answer is;

P(X ≥ 5) = 0.9986

C. Probability of less than 3 of the next 5 business days will be;

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

From online binomial calculator attached, we can see that the answer is;

P(X ≤ 2) = 0.0266

D. Probability of exactly 7 of the next 10 business days will be;

P(X = 7) = C(10, 7) × 0.85^(7) × (1 - 0.85)^(10 - 7)

P(X = 7) = 0.1298

e. Probability of at least 1 of the next 5 business days will be;

P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

From third image attached using online binomial calculator, we have;

P(X ≥ 1) = 0.9999

5 0
3 years ago
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