Answer:
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Step-by-step explanation:
<u>Answer:</u>
a. Look attachment!
b. P1 = 6/11 × 4/10 = 6/11 × 2/5 = 12/55 = (21.82 %)
c. P2 = 5/11 × 6/10 = 5/11 × 3/5 = 15/55 = (27.28 %)
d. P3 = 55/55 - (12/55+15/55) = 55/55 - 27/55 = 28/55 = (50.90 %)
Using the recurrence relation, we can find a couple more values in the sequence:
- a3 = 3a2 -3a1 +a0 = 3(4) -3(2) +2 = 8
- a4 = 3a3 -3a2 +a1 = 3(8) -3(4) +2 = 14
First differences are 0, 2, 4, 6, ...
Second differences are constant at 2, so the function is quadratic.
The sequence can be described by the quadratic ...
... an = n² -n +2
_____
We know the value for n=0 is 2, so we can find <em>a</em> and <em>b</em> using the given values for a1 and a2.
... an = an² +bn +2
... a1 = 2 = a·1² +b·1 +2 . . . . for n=1
... a + b = 0
... a2 = 4 = a·2² -a·2 +2 . . . . for n = 2; using b=-a from the previous equation
... 2 = 2a
... a = 1 . . . . so b = -1
Answer:
X=1 because 2+5=7 then X=1 cause 1*2=2
Step-by-step explanation: