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3 years ago

Help me with this one. pls!!!!

Mathematics

1 answer:

masya89 [10]3 years ago

6 0

<u>Answer:</u>

a. Look attachment!

b. P1 = 6/11 × 4/10 = 6/11 × 2/5 = 12/55 = (21.82 %)

c. P2 = 5/11 × 6/10 = 5/11 × 3/5 = 15/55 = (27.28 %)

d. P3 = 55/55 - (12/55+15/55) = 55/55 - 27/55 = 28/55 = (50.90 %)

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balu736 [363]

See below for the solution to the questions

<h3>The parallel side of the trapezoid</h3>

The given parameters are:

Area = 138

a = 4x - 1

b = x - 4

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The area is calculated as:

Area = 0.5 * (a + b) * height

So, we have:

0.5 *(4x - 1 + x - 4) * 12 = 138

This gives

5x - 5 = 23

Add 5 to both sides

5x = 28

Divide by 5

x = 5.6

Recall that:

a = 4x - 1 = 4 * 5.6 - 1 = 21.4

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<h3>The largest angle in the triangle</h3>

The sides are given as:

x = 22

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The largest angle always opposite the largest side.

This means that the largest angle is Z

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The radius is given as:

r = 29

The circumference is calculated as:

$C = 2\pi r$

So, we have:

$C = 2\pi *29$

Evaluate

C = 182.21

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The measure of the arc is given as:

$\theta = 69^o$

The angle LIK is calculated as:

$m\angle LIK = \frac{\theta}2$

So, we have:

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Evaluate the quotient

$m\angle LIK = 34.5^o$

Hence, the measure of the angle is $m\angle LIK = 34.5^o$

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2 years ago

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Answer:

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(mid-term breaking---4 x 8=32)

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x(x+8)-4(x+8)

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Step-by-step explanation:

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A Merit Rating System for SUTA means:

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The area of the composite solid in the image given is: 399.6 m².

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