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Digiron [165]
3 years ago
6

a teacher wants to give three markers to each of her 25 students markers come in packages of 8 how many packages of markers with

the teacher need
Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0
They would need 10 Packages.
3 markers * 25 students = 75
75/8=9.375
You can't get 9.3 packages 
so you round that up to 10.
Your answer:
10 Packages
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Don't spam!! complete answe= Brainliest answer​
kobusy [5.1K]

Answer:

Step-by-step explanation:

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       = 50 + (-9*8) *1

       = 50 - 9.8

       = 40.2 m/s

2) The acceleration of the ball at its maximum height equals to the force of gravity. -9.8 m/s²

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6 0
2 years ago
Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou
mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

\frac{dQ}{dt} = -kQ

In which k is the decay rate.

The solution is:

Q(t) = Q(0)e^{-kt}

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that Q(0) = 8000

500 counts per minute 13 days later.

This means that Q(13) = 500. We use this to find k.

Q(t) = Q(0)e^{-kt}

500 = 8000e^{-13k}

e^{-13k} = \frac{500}{8000}

\ln{e^{-13k}} = \ln{\frac{500}{8000}}

-13k = \ln{\frac{500}{8000}}

k = -\frac{\ln{\frac{500}{8000}}}{13}

k = 0.2133

So

Q(t) = Q(0)e^{-0.2133t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.2133t}

0.5Q(0) = Q(0)e^{-0.2133t}

e^{-0.2133t} = 0.5

\ln{e^{-0.2133t}} = \ln{0.5}

-0.2133t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.2133}

t = 3.25

The half-life of the radioactive substance is of 3.25 days.

7 0
3 years ago
What divided by 5 equals 6 ? <br><br>? ÷ 5 = 6
stiv31 [10]
30,

because 6×5=30,
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6 0
4 years ago
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Evaluate the following <br><br> |-394|
Irina18 [472]
|-394| = 394 is the answer since all negative absolute values turn positive
7 0
4 years ago
Solve the equation.<br> C3 = 216
Anna [14]

Step-by-step explanation:

C= 72..............

C3=216

C=216

3

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7 0
3 years ago
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