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Softa [21]
2 years ago
9

HELP DUE IN 10 MINUTES!! Solve for x. −2(4x+4) - 3x - 2 = 34

Mathematics
1 answer:
Andrej [43]2 years ago
5 0

Answer:

- 2(4x + 4) - 3x - 2 = 34 \\  \\  - 8x - 8 - 3x - 2 = 34 \\  \\  - 8x -  3x = 34 + 8 + 2 \\  \\  - 11x = 34 + 8 + 2 \\  \\  - 11x = 44 \\  \\ x =  -  \frac{44}{11}  \\  \\ x =  - 4

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How pure is 16-karat gold?
natta225 [31]

Answer:

here

Step-by-step explanation:

16 karat gold is 16 parts gold to 8 parts other material for a pure gold percentage of 67%.

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2 years ago
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What is the midpoint of the segment with two endpoints (4,-6) and (-2,-3)? Put your answers in decimal from, if applicable.
Ber [7]
Answer: 1,-4.5

Explanation: you can find this by finding the difference in y and the difference in x. The difference in x is -6, and the difference in y is +3. All you have to do after that is divide that by 2: -3,1.5, than add that to the first coordinate. That should be the midpoint.
4 0
2 years ago
What set of lengths forms a right triangle?
Leni [432]
The answer is C. 50 in, 48 in, 14 in

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7 0
3 years ago
WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)
IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0
2 years ago
If h(x) = (fºg)(x) and h(x)= 5(x+1)^3 find one possibility for f (x) and g(x).
viktelen [127]

Answer:

One possibility is that;

g(x) = (x + 1)

while h(x) = 5x^3

Step-by-step explanation:

Here, we are told to find one possibility for f(x) and g(x)

The term h(x) = (Fog)(x) means that we are inserting g(x) into f(x) to give h(x)

Now let’s have it this way;

We can see that g(x) = (x + 1) , then h(x) = 5x^3

This is one possibility of the values of g(x) and h(x)

6 0
3 years ago
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