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iogann1982 [59]
3 years ago
13

What would the unit label be for this

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0
The unit label is "degrees". 
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I need help with this... 4 more than some number d. and 3 is less than X. and the others :(
Greeley [361]
2) C: 4+d

3) A: x-3

4) C: 5(1-f)

I know that this is a few weeks late...

but hope this helps!
3 0
3 years ago
Consider the functions:
Zolol [24]

Answer:

The function f(x) was translated right 3 units and up 2 units.

Step-by-step explanation:

F(x)=(2/3)^x

If we move it right for 3 units, we get

f(x)= (2/3)^(x-3)

If we move up 2 units , we get

g(x)= (2/3)^(x-3) +2

7 0
3 years ago
In a café, I order a cup of tea and a piece of cake and it costs £1.10. The next time I order 2 cups of tea and one piece of cak
defon

Answer:

£0.50

Step-by-step explanation:

t = one cup of tea

c = one piece of cake

t + c = £1.10

2t + c = £1.70

the cost increases by £0.60 (£1.70 - £1.10) when you order one more cup of tea which means that one cup of tea costs £0.60

substitute £0.60 into t + c = £1.10

£0.60 + c = £1.10

rearrange to get c = £1.10 - £0.60 = £0.50

so one piece of cake costs £0.50

7 0
3 years ago
Read 2 more answers
Alex says that the function f(x) = (3x)2 represents a vertical stretch of the quadratic parent function by a factor of 3. Marta
gavmur [86]

Our parent function is f(x)=x^2. A vertical stretch by a factor of k means that every point (x,f(x)), has been transformed into (x,kf(x)). Alex is clearly incorrect as our parent function has been transformed to (x,9f(x)), not (x,3f(x)). A horizontal stretch(or compression) by a factor of k means our function has been transformed to (x/k,f(x)). Here, Marta is saying our function should look like (3x,f(x)). This can also be achieved by plugging 3x into the parent function, which would give us f(3x)=(3x)^2, so it seems that Marta is the correct one.

6 0
3 years ago
For questions 6-9, match the equation to its corresponding graph.
Julli [10]
6.b
7.d
8.a
9.c
see attached image. sorry that’s it’s all jumbled up weird, i could only figure out how to put them all together using photoshop. hope these help you out :))

8 0
3 years ago
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