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RideAnS [48]
2 years ago
12

Nine out of ten students prefer math class over lunch. How many students do not prefer math if 200 students were asked

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
4 0

Answer:

i think probably 20

Step-by-step explanation:

if 200 students, students do not prefer math 10/100 × 200 = 20

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NNADVOKAT [17]

Answer:

Step-by-step explanation:

x^2 + 7x + 5x + 35

7x : II

5x: III

35: IV

7 0
3 years ago
PLSS HELP ASAP I WILL GIFE H BRAINLIEAST
valina [46]

Answer:

6 ft^2

Step-by-step explanation:

A=1/2 Base Height

A=1/2(3)(4)

A=6 ft^2

3 0
2 years ago
(x^2-7x)^2+4(x^2-7x)-96 (x 2 −7x) 2 +4(x 2 −7x)−96
natita [175]

Answer:

answer...

Step-by-step explanation:

This is the answer.

6 0
2 years ago
At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
Solve for n<br> N<br> - =7<br> -5
goldfiish [28.3K]

Answer:

N = 14 - 7 = 7 - 5 = 2 is the answer

Step-by-step explanation:

Also My zodiac sign is ♓

7 0
3 years ago
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