Be more specific with the question that you’re asking bc I will love to help
Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
Answer:
p
Step-by-step explanation:
The value of h depends on the values of p.
So h is the dependent variable and p is the independent one
Answer:
0.7 + 0.4 - 0.2 = 0.9
Step-by-step explanation:
Let's denote the probabilities as following:
The probability that the show had animals is
P(A) = 0.7
The probability that the show aired more than 10 times is
P(B) = 0.4
The probability that the show had animals and aired more than 10 times is
P(A⋂B) = 0.2
The probability that a randomly selected show had animals or aired more than 10 times is P(A⋃B)
The correct form of addition rule to determine the probability that a randomly selected show had animals or aired more than 10 times is:
P(A⋃B) = P(A) + P(B) - P(A⋂B) = 0.7 + 0.4 - 0.2 = 0.9
=> Option B is correct
Hope this helps!
Answer:
a think only thing thats close to my data
Step-by-step explanation:
