Answer:
The equation for the variation is:

Step-by-step explanation:
The relationship is given by the quotient between the two variables: (1) distance of the storm, and (2) the number of seconds to hear the thunder. That is:

Hello!
log₃(x) + log₃(x - 6) = log₃(7) <=>
<=> log₃(x * (x - 6)) = log₃(7) <=>
<=> log₃(x² - 6x) = log₃(7) <=>
<=> x² - 6x = 7 <=>
<=> x² - 6x - 7 = 0 <=>
<=> x² + x - 7x - 7 = 0 <=>
<=> x * (x + 1) - 7 * (x + 1) = 0 <=>
<=> (x + 1) * (x - 7) = 0 <=>
<=> x + 1 = 0 and x - 7 = 0 <=>
<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>
<=> x = 7
Good luck! :)
The 3rd option is correct....................
See the attached picture for the histogram. To accomplish this manually, we would have to find the minimum and maximum (1 to 18), decide on the bin size (I used 1 here), and list the frequency of each result. In this case:
1-2 wins - 2
3 wins - 1
4 wins - 2
6 wins - 1
7 wins - 1
8 wins - 1
12 wins - 1
13 wins - 1
15 wins - 2
16 wins - 1
18 wins - 1
Then these are plotted on the histogram.
Answer:
900.
Step-by-step explanation:
1) the initial area is: A₀=0.5*base*h;
2) the final area is: A=0.5*(5*base)*(5*h).
It means, that 25A₀=A, then A=900 [cm²].