<h3>
Hello there today we will solve your problem</h3>
here is our equation,
,
Now we will plug in our numbers
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simplify it and we get



Charlene had more green then red.
so She will run out of red first anyways because its the lowest amount.
Hope this helps....
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Answer:
Small box weighs 13.75 kg & large box weighs 15.75 kg
Step-by-step explanation:
We can write 2 simultaneous equation and solve for weight of each box.
<em>Let weight of large box be l and small box be s.</em>
<em />
"<u>3 large boxes and 5 small boxes has a total weight of 116 kilograms</u>":

and
"<u>9 large boxes and 7 small boxes has a total weight of 238 kilograms</u>":

<em>Now we can solve for l in the 1st equation and put it into 2nd equation and get s:</em>
<em>
</em>
<em>now,</em>
<em>
</em>
<em />
<em>now we plug in 13.75 into s into equation of l to find s:</em>
<em>
</em>
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