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3 years ago

1. Solve the following equation.(MAFS.8.EE.3.7) 5(3x + 7) + 2x = 7x – 5(–2x + 9)

Mathematics

2 answers:

Ksivusya [100]3 years ago

4 0

Answer:

there is no solution

Step-by-step explanation:

Expand.

15x+35+2x=7x+10x-4515x+35+2x=7x+10x−45

2 Simplify 15x+35+2x15x+35+2x to 17x+3517x+35.

17x+35=7x+10x-4517x+35=7x+10x−45

3 Simplify 7x+10x-457x+10x−45 to 17x-4517x−45.

17x+35=17x-4517x+35=17x−45

4 Cancel 17x17x on both sides.

35=-4535=−45

5 Since 35=-4535=−45 is false, there is no solution.

No Solution

adell [148]3 years ago

3 0

Answer:

Your answer is: No solution (There are no values of x that make the equation true.)

Step-by-step explanation:

Hope this helped : )

100% Sure I am Right : )

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Solve the system Also plz show work and what you did and these two equations with x and y the x and y have to be the same in bot

Gala2k [10]

Multply both equations by 2 leaving

x + 2y = 8
x - 2y = -2

Add the equations giving

2x = 6
x = 3

Substitute 3 in the top equation

3 + 2y = 8
2y = -5
y = -2.5

5 0

3 years ago

Which is the range of the function f(x) = (9)×?

Anna [14]

Using it's concept, it is found that the range of the function $f(x) = 9^x$ is given by:

all real numbers greater than 0.

<h3>What is the range of a function?</h3>

It is the set that contains all possible output values for the function.

In this problem, the function is:

$f(x) = 9^x$

For <u>exponential functions without vertical shifts</u>, as is the case in this problem, the range is given by:

all real numbers greater than 0.

More can be learned about the range of a function at brainly.com/question/10891721

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2 years ago

What is the equation of the line that is

sladkih [1.3K]

Answer:

y = 1/2x - 7/2

Step-by-step explanation:

y = 1/2x + b

-3 = 1/2(1) + b

-3 = 1/2 + b

-7/2 = b

5 0

3 years ago

This is on graphing cosine and sine functions!

yawa3891 [41]

Check the picture below.

5 is 1*5, or 5 times greater than 1.

4 0

3 years ago

Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not

IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=4,\ hypotenuse=10$

Substitute:

$4^2+leg^2=10^2$

$16+leg^2=100$ <em>subtract 16 from both sides</em>

$leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}$

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}$

Substitute:

$hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}$

$\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}$

5 0

3 years ago