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9 months ago

Another question from me cause yeah :DDDD

Mathematics

2 answers:

Serggg [28]9 months ago

7 0

361/900 queennnn!!!!!

babymother [125]9 months ago

5 0

Answer:

0.40111111111... OR 361/900

Step-by-step explanation:

(− 3/1 +0.3 (−3/1)+1)^2

Add − 1/3 and 0.3 to get −1/30

(− 1/30− 1/3 +1) ^2

Subtract 3/1 from − 1/30 to get − 11/30

(− 11/30+1)^2.

Add −11/30 and 1 to get 19/30

( 19/30 )^2

Calculate 19/30 to the power of 2 and get 361/900

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Thickness measurement ancient prehistoric Native American Pot Shards discovered in Hopi Village are approximately normally distr

beks73 [17]

Answer:

a) $P(X$

And we can find this probability using the normal standard table and we got:

$P(z$

b) $P(X>7)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z>\frac{7-5.1}{0.9})=P(z>2.11)$

And we can find this probability using the complement rule and the normal standard table and we got:

$P(z>2.11)=1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.1,0.9)$

Where $\mu=5.1$ and $\sigma=0.9$

Part a

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table and we got:

$P(z$

Part b

We are interested on this probability

$P(X>7)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>7)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z>\frac{7-5.1}{0.9})=P(z>2.11)$

And we can find this probability using the complement rule and the normal standard table and we got:

$P(z>2.11)=1-P(Z$

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