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2 years ago

To solve m + 9 = 45, should you add or subtract 9 from both sides of the equation

Mathematics

2 answers:

Lena [83]2 years ago

8 0

Answer:

subtract 9 from both sides

Step-by-step explanation:

m + 9 = 45 ( subtract 9 from both sides )

m = 36

Anastasy [175]2 years ago

6 0

Answer:

Subtract

Step-by-step explanation:

You should subtract since the equation says to add.

You basically do the opposite of what it says.

For example, if it was m - 9 = 45 you would add 9 on both sides, but in this case, you would subtract since its m + 9 = 45

m + 9 = 45

subtract nine by 9 and 45:

m = 36

36 + 9 = 45

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Jessie says to round 736,400 to the nearest ten thousand ,he will round to 770,000. is he right? explain.

djverab [1.8K]

no because if your rounding 736,400 it will be 740,000 if its 4 or less you let it rest if its 5 or more it rises

3 0

3 years ago

Can someone help with these two PLZ.

Alexandra [31]

Answer:

5. 76

6. 24

Step-by-step explanation:

x + x = 152

2x = 152

x = 76

2x + 3x = 120

5x = 120

x = 24

7 0

2 years ago

If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

Write in simple radical form:

WARRIOR [948]

Answer:

The answer to your question is $\frac{2}{3}$

Step-by-step explanation:

Here, there is a difference of squares, so just solve it and simplify

$( 1 + \frac{1}{\sqrt{3} } ) (1 - \frac{1}{\sqrt{3} } )$

Multiply the binomials

= 1 - $\frac{1}{3}$

Simplify

= $\frac{3 - 1}{3}$

= $\frac{2}{3}$

7 0

2 years ago

SOMEONE PLEASE HELP ME !!!!!

Maslowich

The side of the barn is made of 2 shapes, a triangle and a rectangle. Find the area of each shape, then add together to find the total area.

To find the area of the triangle, we multiply 1/2 x (triangle base x triangle height), we can find the triangle height by subtracting the height on the right by the height on the left, so 26.5-14.5 = 12.5ft.

The area of the triangle is 1/2 x (22.8x12.5) = 142.5 square ft.

The area of the rectangle is calculated by multiplying one side by the other, which is 22.8x14.5 = 330.6 square feet.

The total area of the side of the barn is 330.6 + 142.5 = 473.1 square feet.

Since we now know the area of the side of the barn, we can find the cost of paint needed. A one gallon paint can covers 350 square feet and costs $20, but we need to paint 473.1 square feet so we'll need to buy a second can. This means we can easily paint the side of the barn with 2 cans, costing $40 in paint.

5 0

2 years ago