Question

Find the coordinates of centroid of a triangle whose vertices have coordinates (6,2);(- 3, 4); (3,- 9).

Answer 1

$\huge \bf༆ Answer ༄$

Let's solve ~

According to formula, the coordinates of Centroid of a triangle are ;

$\sf x = \dfrac{x_1 + x_2 + x_3 }{3}$

$\sf y = \dfrac{y_1 + y_2 + y_3 }{3}$

So, plug the coordinates of its vertices in the formula to find the required solution !

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = \dfrac{6 + ( - 3) + 3}{3}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = \dfrac{2+ 4 + (- 9) }{3}$

Further solving ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = \dfrac{6}{3}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = \dfrac{ - 3}{3}$

Therefore, the required coordinates are ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 2$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = - 1$

Correct choice is ;

$\overbrace{ \underbrace{\underline{ \boxed{ \sf (2 ,-1)}}}}$