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AlladinOne [14]
3 years ago
15

What is the midpoint of h(7,10),x(5,-8)

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0
See attachment

then we add 7 and 5 and divide that by 2, which gives you 6 (x-coordinate)
and add 10 and -8 and divide that by 2, which gives you 1 (y-coordinate)

the answer is (6, 1)

justification
so midpoint is basically the middle point of 2 points
that's why we have to add the two x coordinates first then divide it by 2
                               or add the two y coordinates then divide it by 2

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Natali [406]

Answer: 5x + 2

Step-by-step explanation:

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Factor 16x2 + 121 over the set of complex numbers.<br> Enter your answer in the box.
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Answer:

(4x - 11i)(4x -+11i)

Step-by-step explanation:

Factor as a difference of squares

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note that i² = - 1

Given

16x² + 121

= (4x)² - (11i)²

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3 years ago
What is the recycle of the beans ​
Elena-2011 [213]

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2 years ago
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12)If p and p' are the length of the perpendiculars drawn from the points (+-root a2-b2,0) to the line x/a cosA + y/b sinA = 1,
Elden [556K]

Answer:

Kindly refer to below explanation.

Step-by-step explanation:

Given equation of line:

\dfrac{x}{a}cos\theta+ \dfrac{y}{b}sin\theta =1\\OR\\\dfrac{x}{a}cos\theta+ \dfrac{y}{b}sin\theta-1=0

Given points are:

(\sqrt{a^2-b^2},0), (-\sqrt{a^2-b^2},0)

Formula for distance between a point and a line is:

If the point is (m, n) and equation of line is Ax+By+C = 0

Then, perpendicular distance between line and points is:

Distance = \dfrac{|Am+Bn+C|}{\sqrt{A^2+B^2}}

Here,

A = \dfrac{x}{a}cos\theta\\B = \dfrac{y}{b}sin\theta\\C = -1

For the first point:

m = \sqrt{a^2-b^2}, n = 0

By the above formula:

p and p' can be calculated as:

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(x+y)(x-y) = x^2 - y^2

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(Using the identity:

sin^2\theta +cos^2\theta = 1)

(Hence provded)

5 0
2 years ago
Pls help if you know the answer thanks! :)
kozerog [31]
Answer:
A- -4/7
B- 2/7
C- 1
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