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Vinil7 [7]
3 years ago
14

The height of a soccer ball thrown of a hill can be modeled by the equation h = -16t^2 -8t +120.

Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:

120 feet

Step-by-step explanation:

You have to find the y-intercept to calculate the initial hight, this can be done by substituting o in for t

h(0)= -16(0)^2-8(0)+120

=120ft

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What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? Enter the equation in the box.
SOVA2 [1]
Notice the picture below

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\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}}) }\\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-----------------------------\\\\

\bf \begin{cases}
p=-1\\
h=-2\\
k=5
\end{cases}\implies (x-(-2))^2=4(-1)(y-5)
\\\\\\
(x+2)^2=-4(y-5)\implies 
-\cfrac{1}{4}(x+2)^2=y-5
\\\\\\
\boxed{-\cfrac{1}{4}(x+2)^2+5=y}

4 0
3 years ago
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Andrej [43]

Answer:

holy this is just substitution child

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5 0
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