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3 years ago

Match The Term

Mathematics

2 answers:

Tatiana [17]3 years ago

5 0

Answer:

Radius matches with option F.

Arc matches with option D.

Chord matches with option C.

Secant matches with option E

Tangent matches with option A

Circumference matches option B

Step-by-step explanation:

Given the diagram in which chord is given, arc is given and secant is given.

we have to match the terms with their characteristics.

Radius is a segment between the centre of a circle and a point on the circle where the distance is same from each point of circumference to center.

Radius matches with option F.

Arc is the portion of the circle between points B and C is darkened represented in figure 2.

Arc matches with option D.

Chord of a circle is a line segment connecting points B and C which are on the circle shown in circle 1.

Chord matches with option C.

Secant is a line segment connecting points B and C which are on the circle shown in circle 3.

Secant matches with option E

Tangent that is a line intersects a circle in exactly one point.

Tangent matches with option A

Circumference is the distance around a circle.

Circumference matches with option B

GalinKa [24]3 years ago

4 0

Answer:

jyyj

Step-by-step explanation:

From the figure,

Radius matches with (F) that is a segment between the centre of a circle and a point on the circle.

Arc matches with (D) that is Circle A and the portion of the circle between points B and C is darkened.

Chord matches with (C) Circle A and a line segment connecting points B and C which are on the circle.

Secant matches with (E) that is Circle A and a line segment connecting points B and C which are on the circle.

Tangent matches with (A) that is a line intersects a circle in exactly one point.

Circumference matches (B) that is the distance around a circle.

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aleksklad [387]

Answer:

price = x * 0.2

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Step-by-step explanation:

In this case we must know either the mass of the cake or its volume.

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Given the case of the volume, we must first multiply the density by this volume in order to calculate the mass and finally the price.

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3 years ago

Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution

Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

$y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\$

for y=e^{6x}:

$y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\$

Now we replace in the differential equation y'' − y' − 30y = 0

for y=e^{-5x}:

$25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0$

for y=e^{6x}:

$36e^{6x}-6e^{6x}-30=0\\36-6+30=0$

Now, to know if both function are linearly independent we calculate the Wronskian

$W(f,g)=fg'-f'g$

$W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0$

I hope this is useful for you

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3 years ago

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Answer:

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n + n + 8 = 12

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