$\log_y{(5)}+\log_y{(y)}=2\\\\\dfrac{\log{(5)}}{\log{(y)}}+1=2 \quad\text{change of base formula}\\\\\dfrac{\log{(5)}}{\log{(y)}}=1 \quad\text{subtract 1}\\\\\log{(5)}=\log{(y)} \quad\text{multiply by log(y)}\\\\5=y \quad\text{take the anti-log}$

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You can also take the antilog first:

5y = y²

y(y -5) = 0 . . . . . subtract 5y, factor

y = 0 or 5 . . . . . y=0 is not a viable solution, so y=5.

5 0

3 years ago

Alex bikes 2 3/4 miles. Then, she runs 1 2/4 miles. The distance she bikes is how many times the distance she runs?

anastassius [24]

Answer:

The distance she bikes is 11/6 times as much as the distance she runs.

Step-by-step explanation:

Alex bikes 2.75 miles, runs 1.5 miles. The distance she bikes is 2.75/1.5 times as much as the distance she runs.

The distance she bikes is 11/6 times as much as the distance she runs.

7 0

2 years ago

Read 2 more answers

the population of masterton was 23 000 in 2012. Assume that Masterton population increases at a rate of 2% per year. Write an eq

Oksanka [162]

So, let's first focus on the first year:

the population then would be: 23000* (100+2)%

100% is the old population the 2% is the incease, so in total it's 102%, or 1.02 - the same number written differently.

So it will be 23000*1.02

After two years it will be 23000*1.02*1.02, and so on

so after x years it will be:

y=23000* $1.02^{z}$

8 0

3 years ago